Respuesta :

genmad

Step-by-step explanation:

we know,

[tex]tn= a {(r)}^{n - 1} \\ T5 = a {(2)}^{5 - 1} \\ t5 = a \times {2}^{4} \\ = 16a[/tex]

Therefore, nth term of a given gp is

16a

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