Which statement about g(x)=βˆ’x2+x+20 is true?

The zeros are βˆ’5 and βˆ’4, because g(x)=βˆ’(x+4)(x+5).

The zeros are βˆ’5 and 4, because g(x)=βˆ’(xβˆ’4)(x+5).

The zeros are βˆ’4 and 5, because g(x)=βˆ’(x+4)(xβˆ’5).

The zeros are 4 and 5, because g(x)=βˆ’(xβˆ’4)(xβˆ’5).

Respuesta :

The zeros are βˆ’4 and 5, because g(x)=βˆ’(x+4)(xβˆ’5).

Zeros of quadratc equation

Given the function Β g(x)=βˆ’x^2+x+20

Factorize the expression

g(x) = -x^2 +5x - 4x + 20

g(x) = -x(x-5)-4(x-5)

g(x) = (-x-4)(x-5)

Equating the result to zero

x - 5 = 0

x = 5

Similarly, -x-4 = 0

-x = 4

x = -4

Hence the zeros are βˆ’4 and 5, because g(x)=βˆ’(x+4)(xβˆ’5)

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