The zeros are β4 and 5, because g(x)=β(x+4)(xβ5).
Given the function Β g(x)=βx^2+x+20
Factorize the expression
g(x) = -x^2 +5x - 4x + 20
g(x) = -x(x-5)-4(x-5)
g(x) = (-x-4)(x-5)
Equating the result to zero
x - 5 = 0
x = 5
Similarly, -x-4 = 0
-x = 4
x = -4
Hence the zeros are β4 and 5, because g(x)=β(x+4)(xβ5)
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