sarahiouslyy
sarahiouslyy sarahiouslyy
  • 03-05-2017
  • Mathematics
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What is the trigonometric expression of sec^2x - 1 divided by sec^2x ??

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ghanami
ghanami ghanami
  • 06-05-2017
hello : 
(sec²x - 1) / sec²x  = (sec²x / sec²x) -1/sec²x
                             = 1 -1/sec²x
                             = 1- (1/secx)²
                              = 1 -cos²x
                              = sin²x
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